Convergence of Measures and Metrizability
This article should address metrizability for both narrow and wide convergence.
General Functional Analysis Refs
- Ambrosio, Gigli, Savaré (107-108), Brezis (72-76)
Narrow Convergence
- Unit ball of dual space of is, in general, not metrizable: [Conway, A Course in Functional Analysis, Theorem 6.6]
- It is metrizable when restricted to probability measures: Ambrosio, Gigli, Savaré (106-108)
Wide Convergence
- On the other hand, if X is a metrizable locally compact space that is σ-compact, then is separable, [Conway, A Course in Functional Analysis, III. Banach Spaces, exercise 14]
Weak-star topologies
Given a Banach space and its Banach dual , the dual can be endowed with the weakest topology that makes the evaluation maps at elements of continuous. This is called the weak-star topology relative to . By Banach-Alaoglu, the unit ball of (which we call ) with the weak-star topology is compact.
In the case where is norm separable, the weak-star topology on the unit ball of can, in fact, be metrized. Fix a sequence that is countable and dense in . Define the metric by . This is a sum of pseudometrics, necessarily convergent because each term is less than or equal to , and is nondegenerate because if , then for each , which would imply that the continuous functions agreed on a dense subset of a metric space. The identity map from to is continuous: choose a net . Then for each , perform the following truncation process: choose a large so that . Because , for each , there is some large such that for all , . By the net order axioms, there is some large Failed to parse (syntax error): {\displaystyle \gamma_0\succeq\gamma_i\:\forall i\in\{1,\ldots,N\}} . So for each , . Now the identity map between the two spaces is a continuous bijection between a compact and a Hausdorff topological space, and is therefore a homeomorphism. So it metrizes the weak-star topology.