Beppo-Levi Theorem: Difference between revisions

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==Statement==
==Statement==
Let <math>(X,\Sigma, \mu)</math> be the underlying measure space and let <math>\{f_{n}\}_{n=1}^{\infty}</math> be a sequence of non-negative, measurable functions with <math>f_{n}: X \rightarrow [0, +\infty]</math>. Then, <math> \sum_{n=1}^{\infty}\int f_{n}d\mu = \int \sum_{n=1}^{\infty}f_{n} d\mu </math>
Let <math>(X,\Sigma, \mu)</math> be the underlying measure space and let <math>\{f_{n}\}_{n=1}^{\infty}</math> be a sequence of measurable functions with <math>f_{n}: X \rightarrow [0, +\infty]</math>. Then, <math> \sum_{n=1}^{\infty}\int f_{n}d\mu = \int \sum_{n=1}^{\infty}f_{n} d\mu </math>


==Proof==
==Proof==
First, the result is proved for finite sums. Take <math>f, g: X\rightarrow [0, +\infty]</math> measurable functions. As such, take sequences <math> \{\phi_{j}\}_{j=1}^{\infty}</math> and <math> \{\psi_{j}\}_{j=1}^{\infty}</math> so that they converge pointwise to <math>f</math> and <math>g</math> respectively.
First, the result is proved for finite sums. Take <math>f, g: X\rightarrow [0, +\infty]</math> measurable functions. As such, take sequences <math> \{\phi_{j}\}_{j=1}^{\infty}</math> and <math> \{\psi_{j}\}_{j=1}^{\infty}</math> so that they converge pointwise to <math>f</math> and <math>g</math> respectively.

Revision as of 22:27, 3 December 2020

The Beppo-Levi theorem is a result in measure theory that gives us conditions wherein we may then pass the integral through an infinite series of functions. That is to say, this theorem provides conditions under which the (possibly infinite) sum of the integrals is equal to the integral of the sums.

Statement

Let be the underlying measure space and let be a sequence of measurable functions with . Then,

Proof

First, the result is proved for finite sums. Take measurable functions. As such, take sequences and so that they converge pointwise to and respectively.