Optimal Transport and Ricci curvature: Difference between revisions

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Notice that this inequality involves the transport map <math> T </math> and the Ricci curvature tensor and therefore constitutes a connection of the curvature and the optimal transport problem.
Notice that this inequality involves the transport map <math> T </math> and the Ricci curvature tensor and therefore constitutes a connection of the curvature and the optimal transport problem.


Before we prove the Proposition, let us do some remarks: notice that for any <math>i=1,\dots, n</math> the map <math> t \mapsto \partial _i T_t(x)</math> is a Jacobi field along the geodesic <math> t \mapsto \exp_x(t\xi(x)),</math> where <math> \partial_i </math> is the partial derivative induced by a chart around <math> x </math>.
===Remarks===
Before we prove the Proposition, let us do some remarks: let <math> x \in M </math> be given and let <math> e_i </math> for <math> i = 1, \dots, n </math> be an orthonormal basis. After doing parallel transport along <math> \gamma</math>, we have an orthonormal basis also in <math> T_{T_t(x)}M</math>.  Let <math> \textbf J</math> denote the matrix representation of  <math> d_xT_t: T_xM\rightarrow T_{T_t(x)}M.</math> Then we have that
<math> J''+RJ=0</math>
where <math> R</math> denotes the matrix <math>(R(\gamma', e_i,\gamma', e_j))_{i,j}.
Then we have that <math> J_i(t):= d_xT_t(e_i)</math> is a Jacobi field along <math> \gamma</math>. Now let


==References==
==References==

Revision as of 23:36, 14 February 2022

Introduction and Motivation

This article provides a brief introduction into a connection of optimal transport and the curvature tensor of a Riemannian manifold. In fact, we are going to study the transport map where denotes a vector field on the manifold

These kind of maps appear very naturally in the context of optimal transport. Recall that in optimal transport one is particularly interested in the Monge Problem, being the following optimization problem: Let be a compact and connected Riemannian manifold. Let furthermore, denote two probability measures on which are absolutely continuous with respect to the measure on the manifold, induced by the metric. the Monge Problem is then given by

               

where the infimum is taken among all measurable maps and denotes the Metric on induced by Then the Monge Problem admits a unique solution Moreover, in that case

         

for some (see [1]for more details of this).

To conclude the introductory part of this article, let us also mention that these kind of transport maps, turned out to be useful in the area of geometric analysis. In fact, Simon Brendle could prove a Sobolev inequality on non compact Riemannian manifolds with nonnegative Ricci curvature, the proof of which makes use of defining a map which is of the type ( see proof of Theorem 1.1 in [2] for more details).

Curvature and Optimal Transport

Let be a Riemannian manifold. In this article we assume basic knowledge about the notions of curvature and geodesics on a manifold. For some background information on these topics, we refer the reader to Chapter three to five in [3].

The Goal of this article is to show the follwing

Proposition

Let where denotes a vector field on and let Then the following inequality holds true:

  

where is defined to be the mapping which is a geodesic.


Notice that this inequality involves the transport map and the Ricci curvature tensor and therefore constitutes a connection of the curvature and the optimal transport problem.

Remarks

Before we prove the Proposition, let us do some remarks: let be given and let for be an orthonormal basis. After doing parallel transport along , we have an orthonormal basis also in . Let denote the matrix representation of Then we have that where denotes the matrix is a Jacobi field along . Now let

References