Dominated Convergence Theorem: Difference between revisions

From Optimal Transport Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 7: Line 7:


==Proof of Theorem==
==Proof of Theorem==
<math>f</math> is a measurable function in the sense that it is a.e. equal to a measurable function, since it is the limit of <math>f_n</math> except on a null set. Also <math>f \leq g</math> a.e., so <math>f \in L^1(\lambda)</math>.
<math>f</math> is a measurable function in the sense that it is a.e. equal to a measurable function, since it is the limit of <math>f_n</math> except on a null set. Also <math>|f| \leq g</math> a.e., so <math>f \in L^1(\lambda)</math>.
 
Now we have <math>g + f_n \geq 0</math> a.e. and <math>g - f_n \geq 0</math> a.e. to which we may apply Fatou's lemma to obtain
 
<math>\int g + \int f = \int \lim_{n \to \infty} (g + f_n) \leq \liminf_{n \to \infty} \int (g + f_n) = \int g + \liminf_{n \to \infty} \int f_n</math>,
 
where the equalities follow from linearity of the integral and the inequality follows from Fatou's lemma. We similarly obtain
 
<math>\int g - \int f = \int \lim_{n \to \infty} (g - f_n) \leq \liminf_{n \to \infty} \int (g - f_n) = \int g - \limsup_{n \to \infty} \int f_n</math>.
 
Since <math>\int g < +\infty</math>, these imply
 
<math>\limsup_{n \to \infty} \int f_n \leq \int f \leq \liminf_{n \to \infty} \int f_n</math> from which the result follows.

Revision as of 08:49, 18 December 2020

In measure theory, the dominated convergence theorem is a cornerstone of Lebesgue integration. It can be viewed as a culmination of all efforts, and is a general statement about the interplay between limits and integrals.

Theorem Statement

Consider the measure space . Suppose is a sequence in such that

  1. a.e
  2. there exists such that a.e. for all

Then and .

Proof of Theorem

is a measurable function in the sense that it is a.e. equal to a measurable function, since it is the limit of except on a null set. Also a.e., so .

Now we have a.e. and a.e. to which we may apply Fatou's lemma to obtain

,

where the equalities follow from linearity of the integral and the inequality follows from Fatou's lemma. We similarly obtain

.

Since , these imply

from which the result follows.