L1 Space: Difference between revisions
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<b>Definition:</b> | <b>Definition:</b> | ||
Let <math>L^1</math> denote the set of integrable functions on <math>X</math>, ie <math>\int |f| <\infty</math>. Define an equivalence relation: <math>f\sim g</math> if <math>f=g</math> a.e. Then <math>L^1(\mu)= L^1/\sim</math>. | Let <math>L^1</math> denote the set of integrable functions on <math>X</math>, ie <math>\int |f| <\infty</math>. Define an equivalence relation: <math>f\sim g</math> if <math>f=g</math> a.e. Then <math>L^1(\mu)= L^1/\sim</math>. | ||
To make sense of the definition, we need the following proposition: | |||
<b> Proposition:</b> Let <math>f,g\in L^1</math>, then the following are equivalent: | |||
<ol> | |||
<il> <math>\int_E f=\int_E g,</math> for all <math>E\in\mathcal{M}</math> | |||
<il><math>\int |f-g|=0 | |||
<il> <math>f=g</math> a.e. | |||
==References== | ==References== |
Revision as of 08:42, 15 December 2020
Introduction
Let be a measure space. From our study of integration, we know that if are integrable functions, the following functions are also integrable:
- , for
This shows that the set of integrable functions on any measurable space is a vector space. Furthermore, integration is a linear functional on this vector space, ie a linear function sending elements in our vector space to , one would like to use integration to define a norm on our vector space. However, if one were to check the axioms for a norm, one finds that if almost everywhere, then . This motivates our definition of to be the set of integrable functions up to equivalence to sets of measure zero.
Space
In this section, we will construct .
Definition: Let denote the set of integrable functions on , ie . Define an equivalence relation: if a.e. Then .
To make sense of the definition, we need the following proposition:
Proposition: Let , then the following are equivalent:
-
<il> for all
<il> a.e.