Convergence of Measures and Metrizability: Difference between revisions
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Given a Banach space <math>X</math> and its Banach dual <math>X^*</math>, the dual can be endowed with the weakest topology that makes the evaluation maps at elements of <math>X</math> continuous. This is called the <b>weak-star topology relative to <math>X</math></b>. By Banach-Alaoglu, the unit ball of <math>X^*</math> (which we call <math>(X^*)_1</math>) with the weak-star topology is compact. | Given a Banach space <math>X</math> and its Banach dual <math>X^*</math>, the dual can be endowed with the weakest topology that makes the evaluation maps at elements of <math>X</math> continuous. This is called the <b>weak-star topology relative to <math>X</math></b>. By Banach-Alaoglu, the unit ball of <math>X^*</math> (which we call <math>(X^*)_1</math>) with the weak-star topology is compact. | ||
In the case where <math>X</math> is norm separable, the weak-star topology on the unit ball of <math>X^*</math> can, in fact, be metrized. Fix a sequence <math>\{x_n\}_{n=1}^\infty</math> that is countable and dense in <math>X</math>. Define the metric <math>d</math> by <math> d(\phi,\psi):=\sum_{n=0}^\infty 2^{-n}\frac{|\phi(x_n)-\psi(x_n)|}{1+|\phi(x_n)-\psi(x_n)|}</math>. This is a sum of pseudometrics, necessarily convergent because each term is less than or equal to <math>2^{-n}</math>, and is nondegenerate because if <math>d(\phi,\psi)=0</math>, then <math> \phi(x_n)=\psi(x_n)</math> for each <math>x_n</math>, which would imply that the continuous functions <math>\phi,\psi</math> agreed on a dense subset of a metric space. The identity map from <math>((X^*)_1,w*)</math> to <math>((X^*)_1,d)</math> is continuous: choose a net <math>(\phi_\gamma)_{\gamma\in\Gamma} \to \phi</math>. Then for each <math>\epsilon>0</math>, perform the following truncation process: choose a large <math>N</math> so that <math>\sum_{n=N+1}^\infty 2^{-n}=2^{-N}<\frac{\epsilon}{2}</math>. Because <math>\phi_\gamma\xrightarrow{w*}\phi</math>, for each <math>n\in\{1,\ldots,N\}</math>, there is some large <math>\gamma_n</math> such that for all <math>\gamma\succeq\gamma_n</math>, <math>|\phi_\gamma(x_n)-\phi(x-n)|<\frac{\epsilon}{2\cdot N\cdot 2^{-n}}</math>. By the net order axioms, there is some large <math>\gamma_0\succeq\gamma_i | In the case where <math>X</math> is norm separable, the weak-star topology on the unit ball of <math>X^*</math> can, in fact, be metrized. Fix a sequence <math>\{x_n\}_{n=1}^\infty</math> that is countable and dense in <math>X</math>. Define the metric <math>d</math> by <math> d(\phi,\psi):=\sum_{n=0}^\infty 2^{-n}\frac{|\phi(x_n)-\psi(x_n)|}{1+|\phi(x_n)-\psi(x_n)|}</math>. This is a sum of pseudometrics, necessarily convergent because each term is less than or equal to <math>2^{-n}</math>, and is nondegenerate because if <math>d(\phi,\psi)=0</math>, then <math> \phi(x_n)=\psi(x_n)</math> for each <math>x_n</math>, which would imply that the continuous functions <math>\phi,\psi</math> agreed on a dense subset of a metric space. The identity map from <math>((X^*)_1,w*)</math> to <math>((X^*)_1,d)</math> is continuous: choose a net <math>(\phi_\gamma)_{\gamma\in\Gamma} \to \phi</math>. Then for each <math>\epsilon>0</math>, perform the following truncation process: choose a large <math>N</math> so that <math>\sum_{n=N+1}^\infty 2^{-n}=2^{-N}<\frac{\epsilon}{2}</math>. Because <math>\phi_\gamma\xrightarrow{w*}\phi</math>, for each <math>n\in\{1,\ldots,N\}</math>, there is some large <math>\gamma_n</math> such that for all <math>\gamma\succeq\gamma_n</math>, <math>|\phi_\gamma(x_n)-\phi(x-n)|<\frac{\epsilon}{2\cdot N\cdot 2^{-n}}</math>. By the net order axioms, there is some large <math>\gamma_0\succeq\gamma_i\forall i\in\{1,\ldots,N\}</math>. So for each <math>\gamma\succeq \gamma_0</math>, <math>d(\phi_\gamma,\phi)<\sum_{n=1}^N \frac{1}{2N}+\sum_{n=N+1}^\infty 2^{-n}<\epsilon</math>. Now the identity map between the two spaces is a continuous bijection between a compact and a Hausdorff topological space, and is therefore a homeomorphism. So it metrizes the weak-star topology. |
Revision as of 01:44, 5 May 2020
This article should address metrizability for both narrow and wide convergence.
General Functional Analysis Refs
- Ambrosio, Gigli, Savaré (107-108), Brezis (72-76)
Narrow Convergence
- Unit ball of dual space of is, in general, not metrizable: [Conway, A Course in Functional Analysis, Theorem 6.6]
- It is metrizable when restricted to probability measures: Ambrosio, Gigli, Savaré (106-108)
Wide Convergence
- On the other hand, if X is a metrizable locally compact space that is σ-compact, then is separable, [Conway, A Course in Functional Analysis, III. Banach Spaces, exercise 14]
Weak-star topologies
Given a Banach space and its Banach dual , the dual can be endowed with the weakest topology that makes the evaluation maps at elements of continuous. This is called the weak-star topology relative to . By Banach-Alaoglu, the unit ball of (which we call ) with the weak-star topology is compact.
In the case where is norm separable, the weak-star topology on the unit ball of can, in fact, be metrized. Fix a sequence that is countable and dense in . Define the metric by . This is a sum of pseudometrics, necessarily convergent because each term is less than or equal to , and is nondegenerate because if , then for each , which would imply that the continuous functions agreed on a dense subset of a metric space. The identity map from to is continuous: choose a net . Then for each , perform the following truncation process: choose a large so that . Because , for each , there is some large such that for all , . By the net order axioms, there is some large . So for each , . Now the identity map between the two spaces is a continuous bijection between a compact and a Hausdorff topological space, and is therefore a homeomorphism. So it metrizes the weak-star topology.